Electronics and Communication Engineering - Signals and Systems - Discussion
Discussion Forum : Signals and Systems - Section 1 (Q.No. 1)
1.
What about the stability of system in 
Answer: Option
Explanation:
ROC include the unit circle hence it is stable.
Discussion:
50 comments Page 3 of 5.
Shamsheer said:
1 decade ago
ROC is |Z|>2 and .4<|Z|<4/3.
Why everyone are concerned with pole Z=2?
Why everyone are concerned with pole Z=2?
PRADY said:
5 months ago
The system is unstable as the poles are not inside ie. Z<I1I Not satisfies.
S.p.Bharath said:
1 decade ago
The pole Z=2 lies outside the unity circle. Then how can we say it as stable ?
Raam said:
1 decade ago
One of the pole z=2 lies outside the unit circle, so the system is unstable.
Zahoor said:
8 years ago
Since one pole magnitude lies outside the unit circle so system is unstable.
Ramasubramanian said:
7 years ago
The system is unstable since the pole z=2 lies outside the UNIT circle.
D.SIVASAMY said:
8 years ago
System is unstable because pole 2 locating outside the unit circle.
Ajay kumar sharma said:
1 decade ago
Pole doesn't lies b/w the circle so the system is not stable.
Salman said:
5 years ago
The ROC for the non causal signal is? Can anyone answer this?
Dhivya said:
8 years ago
Can anyone please explain how to solve these type of problem?
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