Electronics and Communication Engineering - Signals and Systems - Discussion

Discussion Forum : Signals and Systems - Section 2 (Q.No. 17)
17.
Which one is time invariant system?
y[n] = x[2n]
y[n] = x[n] x[n - 1]
y[n] = x[n/2]
all
Answer: Option
Explanation:

For time invariant system

y(n, k) = y(n - k), where y(n, k) mean shift the input by n - k, while y(n - k) mean change all the n

(a) y[n] = x[2n]

y(n, k) = x[2n - k]

y(n - k) = x[2(n - k)]

y(n, k) ≠ y(n - k) Time variant

(b) y[n] = x[n] x[n - 1]

y[n, k] = x[n - k] x[n - k - 1]

y[n - k] = x[n - k] x[n - k - 1]

y[n, k] = x[n - k] Time Invariant

(c) y[n] = x[n/2] ⇒ y[n, k]

y[n - k]

y[n, k] ≠ y[n - k] Time variant.

Discussion:
1 comments Page 1 of 1.

Yogesh said:   9 years ago
Excellent! Good explanation.

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