Electronics and Communication Engineering - Signals and Systems - Discussion
Discussion Forum : Signals and Systems - Section 1 (Q.No. 38)
38.
Two function g1(t) and g2(t) with correlation of 6 has average power of 4 and 5 respectively. The power of g1(t) + g2(t) is
Answer: Option
Explanation:
Power of two correlated signal is P = P1 + P2 +2R1, 2(t).
Discussion:
3 comments Page 1 of 1.
Radha krishna said:
1 decade ago
I can't understand the answer. Please explain briefly.
Abinash said:
1 decade ago
4+5+2*(6) = 21, two signals g1 & g2, when we find power of g1+g2 that is integration (|g1+g2|^2) we get p1+p2+2r1, 2(t).
Shinykiran said:
10 years ago
@Radha.
g1(t) = P1 = 4, g2(t) = P2 = 5 and R1 = 6.
Then, P1+P2+2R1 = 4+5+2*6 = 21.
g1(t) = P1 = 4, g2(t) = P2 = 5 and R1 = 6.
Then, P1+P2+2R1 = 4+5+2*6 = 21.
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