Electronics and Communication Engineering - Radio Receivers - Discussion
Discussion Forum : Radio Receivers - Section 1 (Q.No. 26)
26.
In a superheterodyne receiver, the IF is 455 kHz. If it is tuned to 1200 kHz, the image frequency will be
Answer: Option
Explanation:
A signal (image) can interfere with a superheterodyne receiver if fits the following equation.
Image = Signal +/- 2 x I.F.
Which says that a signal has the capacity to interfere with a superhet receiver if its frequency is equal to the signal frequency (1200 kHz in our question) plus or minus twice the IF (455 kHz in our question).
So one possible image is: 1200 + ( 2 x 455 ) = 2110 kHz (possible).
And the other: 1200 - ( 2 x 455 ) = 290 kHz (not likely).
Discussion:
3 comments Page 1 of 1.
Pinky said:
5 years ago
Sfi(image frqency) = si(tuned or input signal) + 2 * (intermediate frequency).
Sfi = 1200+2*(455).
Sfi = 2110.
Sfi = 1200+2*(455).
Sfi = 2110.
PIGS said:
9 years ago
Elaborate this answer.
Hamsa said:
1 decade ago
Explain this?
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