Electronics and Communication Engineering - Radio Receivers - Discussion
Discussion Forum : Radio Receivers - Section 2 (Q.No. 14)
14.
When a superheterodyne receiver is tuned to 455 kHz, its local oscillator provides a mixer with the input at 1010 kHz. The image frequency is
Discussion:
9 comments Page 1 of 1.
Yogesh Yadav said:
6 years ago
IF = 455 KHz,
Fo = 1010 KHz,
Fo = Fs + Fi.
1010 KHz = Fs + 455 KHz.
Fs = 555 KHz,
Fsi = Fs + 2Fi,
Fsi = 555 KHz + 910 KHz = 1465 KHz.
Fo = 1010 KHz,
Fo = Fs + Fi.
1010 KHz = Fs + 455 KHz.
Fs = 555 KHz,
Fsi = Fs + 2Fi,
Fsi = 555 KHz + 910 KHz = 1465 KHz.
(2)
Rajeev said:
7 years ago
Yes, you are right @Manoj.
Yoj said:
7 years ago
Yes, you are correct Manoj.
Manoj said:
8 years ago
Fsi = Fo+Fi.
Fsi= 1010+455,
1465.
Fsi= 1010+455,
1465.
Fito said:
8 years ago
Thanks for explaining the answer.
Duresh said:
9 years ago
The formulae is image frequency = signal frequency + 2 * if.
Is it right or wrong?
Is it right or wrong?
Mohammad arshad said:
1 decade ago
Signal freq = if - oscillator freq.
= 1010-455.
= 555.
Image feq = signal freq + 2*oscillator freq.
= 555+2*455.
= 1465.
= 1010-455.
= 555.
Image feq = signal freq + 2*oscillator freq.
= 555+2*455.
= 1465.
Manish kumar said:
1 decade ago
Image frequency = Desired signal frequency+2IF.
= 1010+2*455 = 1920.
= 1010+2*455 = 1920.
Puja said:
1 decade ago
How to calculate this?
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