29.

In a broadcast superheterodynes receiver having no RF amplifier, the loaded Q of the antenna coupling circuit is 100. If the intermediate frequency is 455 kHz. The rejection ratio at 25 MHz will be

 [A]. 1.116 [B]. 1.386 [C]. 2.116 [D]. 2.386

Explanation:

No answer description available for this question.

 Manu said: (Nov 6, 2015) Explain please!

 Moon said: (Jul 29, 2016) Please explain how.

 Jam said: (Dec 8, 2016) Kindly explain it.

 Venkat said: (Dec 28, 2016) Please explain it.

 Ram Charan said: (Jan 3, 2017) F (i.f.) =455khz, f = 25Mhz, Q = 10 here f(s.i) means imaginary frequence. Rejection ratio = sqrt (1+Q^2P^2). Here P = (f(s.i)/f - f(s)/f(s.i)). F(s.i) = f + 2f(i.f). = 25000+2 * 455. F(s.i) = 25910. P= {(25910/25000) - (25000/25910)}. = .0716. Rejection ratio = sqrt(1+Q^2P^2). Total solve R.r.=1.116 approx.

 Rishi Ram Sharma said: (May 4, 2017) No, If Q=100 than Rejection Ratio at 25 MHZ should be near 7.22. Because of R. R = Sqrt(1+Q^2*P^2). Where P is same as Ram Charan Calculated. If Q=10 than Rejection Ratio at 25 MHZ should be near 1.226. Because of R. R=Sqrt(1+Q^2*P^2). Where P is same as Ram Charan Calculated.

 Jay said: (Aug 11, 2018) Yes, I agree with you @Rishi Ram.

 Ebenezer said: (Sep 20, 2018) It should be 7.22.