Electronics and Communication Engineering - Radio Receivers - Discussion
Discussion Forum : Radio Receivers - Section 1 (Q.No. 22)
22.
In a broadcast superheterodynes receiver having no RF amplifier, the loaded Q of the antenna coupling circuit is 100. If the intermediate frequency is 455 kHz. The image frequency at 25 MHz will be
Discussion:
7 comments Page 1 of 1.
Prem said:
7 years ago
What is a Superheterodyne Receiver? Explain it.
(1)
Vanshri said:
1 decade ago
Image freq,
fsi = fs+2fi.
fs = 25 and fi=455.
By solving ans = 25.91 Mhz.
fsi = fs+2fi.
fs = 25 and fi=455.
By solving ans = 25.91 Mhz.
Hamsa said:
1 decade ago
Explain this please.
Sagar said:
9 years ago
Please explain it in detail.
Ali said:
9 years ago
Fc = 25 Mhz, Fi = 455khz
Image frequency fsi = 25mhz + 2(455)khz.
= 25,910.
Image frequency fsi = 25mhz + 2(455)khz.
= 25,910.
Pooja said:
8 years ago
Fs=25Mhz, IF=455Khz.
fsi =Fs+2IF=25910000.
= 25.91Mhz.
fsi =Fs+2IF=25910000.
= 25.91Mhz.
Deepali said:
5 years ago
Fs = 25MHz.
Fi = 455KHz = 455/1000 MHz =0.455.
Fsi=Fs+2Fi.
= 25 + 2(0.455).
Fsi = 25.91MHz.
Fi = 455KHz = 455/1000 MHz =0.455.
Fsi=Fs+2Fi.
= 25 + 2(0.455).
Fsi = 25.91MHz.
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