Electronics and Communication Engineering - Power Electronics - Discussion
Discussion Forum : Power Electronics - Section 5 (Q.No. 46)
46.
The turn on characteristics of a power transistor can be assumed to be linear, as shown in the below figure . During turn on time T, voltage reduces linearly from V to 0 and current rises linearly from 0 to I. The energy loss during time T is
VIT
Discussion:
2 comments Page 1 of 1.
Skemberloshka said:
7 years ago
How? Explain me.
Montano said:
5 years ago
Energy = integral of P with respect to t.
we can express i(t) = (I/T)t and v(t) = (-V/T)t + V.
P(t) = v(t)i(t) = (-IV/T^2)t^2 + (VI/T)t.
integral of (-VI/T^2)t^2 + (VI/T)t from 0 to T.
-VIT/3 +VIT/2 = VIT/6.
we can express i(t) = (I/T)t and v(t) = (-V/T)t + V.
P(t) = v(t)i(t) = (-IV/T^2)t^2 + (VI/T)t.
integral of (-VI/T^2)t^2 + (VI/T)t from 0 to T.
-VIT/3 +VIT/2 = VIT/6.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers