Electronics and Communication Engineering - Networks Analysis and Synthesis - Discussion

Discussion Forum : Networks Analysis and Synthesis - Section 2 (Q.No. 27)

Networks Analysis and Synthesis

27.

Assertion (A): is positive real.

Reason (R): For a positive real function Re[H(jω)] ≥ 0 for 0 ≤ ω ≤ ∞.

Both A and R are true and R is correct explanation of A

Both A and R are true and R is not the correct explanation of A

A is true but R is false

A is false but R is true

Answer: Option

Explanation:

A is not positive real.

Discussion:

2 comments Page 1 of 1.

Diwakar said: 8 years ago

From 2nd condition, if you put any value of w>0, the value of z (S) must be real which is not happening for w=1. So, it is not a real function.

Shyam narwade said: 1 decade ago

Can anyone explain it please?

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