Electronics and Communication Engineering - Networks Analysis and Synthesis - Discussion
Discussion Forum : Networks Analysis and Synthesis - Section 1 (Q.No. 13)
13.
Z(c) for the network shown in the figure is 
The value of C and R are, respectively
The value of C and R are, respectivelyDiscussion:
22 comments Page 2 of 3.
Arnab said:
8 years ago
After continued fraction expansion you get;
3+{1/(s/6)+{1/(4)+{1/(s/2)+2}}}
C=1/6, R=4.
3+{1/(s/6)+{1/(4)+{1/(s/2)+2}}}
C=1/6, R=4.
Hari said:
8 years ago
@Gopal Agarwal.
I didn't understand that. Please make it clear.
I didn't understand that. Please make it clear.
Prem said:
1 decade ago
Could you please provide explanation for this by formula?
Mahesh said:
9 years ago
Please explain it.
Surya said:
9 years ago
@Satyam is correct.
Put s = 0, where the capacitor is open circuited, then find the equivalent impedance. After that put s = 0 in given z (s) that is get z (0). Equate this with the previous result and get R and in option, there is only one option with R = 4. So A is the right answer.
Put s = 0, where the capacitor is open circuited, then find the equivalent impedance. After that put s = 0 in given z (s) that is get z (0). Equate this with the previous result and get R and in option, there is only one option with R = 4. So A is the right answer.
Anusha sri said:
9 years ago
Please explain in detail.
Amit kumar said:
10 years ago
Please explain this question.
Vini said:
1 decade ago
Calculate impedance and compare?
Manikumar said:
1 decade ago
Add admittances of cap and res = (S/2)+1.
Then sum res = R+(2/S+2).
Add admittances = (CS)+(S+2/(R*(S+2)+2)).
Total = 3+(R*(S+2)+2))/(CS(R*(S+2)+2)) + (S+2));
Then sum res = R+(2/S+2).
Add admittances = (CS)+(S+2/(R*(S+2)+2)).
Total = 3+(R*(S+2)+2))/(CS(R*(S+2)+2)) + (S+2));
James said:
1 decade ago
Can you explain with formula?
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