Electronics and Communication Engineering - Networks Analysis and Synthesis - Discussion
Discussion Forum : Networks Analysis and Synthesis - Section 1 (Q.No. 13)
13.
Z(c) for the network shown in the figure is 
The value of C and R are, respectively
The value of C and R are, respectivelyDiscussion:
22 comments Page 2 of 3.
Mahesh said:
9 years ago
Please explain it.
Akshey said:
9 years ago
What if option b is 2/9 F and 4 ohm. Is it also an answer?
Gopal agarwal said:
8 years ago
TRANSFER FUNCTION COMES OUT AS -: (2+2*R+s*R) + 3*[RC*s^2+s*(2*C+2*R*C+1)+2]
------------------------------------------------------------------------
RC*s^2+s*(2*C+2*R*C+1)+2.
From Denominator-:RC*s^2+s*(2*C+2*C*R+1)+2.
===== RC[ s^2 + s*(2/R+2+1/RC) + 2/RC].
And on comparing it from given equation(i.e. s^2+4*s+3 )
We get 3=2/RC ---> (1)
and from given option, only option (A) satisfy this condition.
that's why the answer is an option (A).
------------------------------------------------------------------------
RC*s^2+s*(2*C+2*R*C+1)+2.
From Denominator-:RC*s^2+s*(2*C+2*C*R+1)+2.
===== RC[ s^2 + s*(2/R+2+1/RC) + 2/RC].
And on comparing it from given equation(i.e. s^2+4*s+3 )
We get 3=2/RC ---> (1)
and from given option, only option (A) satisfy this condition.
that's why the answer is an option (A).
(1)
Hari said:
8 years ago
@Gopal Agarwal.
I didn't understand that. Please make it clear.
I didn't understand that. Please make it clear.
Arnab said:
8 years ago
After continued fraction expansion you get;
3+{1/(s/6)+{1/(4)+{1/(s/2)+2}}}
C=1/6, R=4.
3+{1/(s/6)+{1/(4)+{1/(s/2)+2}}}
C=1/6, R=4.
Ravi said:
8 years ago
Thanks @Satyam.
Roopa said:
8 years ago
Thank you @Satyam.
Surya Dubey said:
7 years ago
Thank you @Satyam.
Saanvi said:
7 years ago
Can anyone explain this problem in detail?
Hephzibah said:
7 years ago
Please solve problem.
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