Electronics and Communication Engineering - Networks Analysis and Synthesis - Discussion
Discussion Forum : Networks Analysis and Synthesis - Section 1 (Q.No. 8)
8.
and i(t) is a unit step, then V(t) in the steady state is given byAnswer: Option
Explanation:
= 4/9.
Discussion:
4 comments Page 1 of 1.
Kalyani said:
3 years ago
Can anyone explain L'hospitals rule?
Megha said:
1 decade ago
See Laplace transformation of a unit step signal is 1/s. And since,
V(s /I(s) = (s+4)/(s+3)^2.
On substituting the value of I (S) i.e. 1/s we get.
V(s) = I(s)*(s+4)/(s+3)^2.
= (s+4)/((s)(s+3)^2).
Now when you use the formula for the steady state i.e. limit s->0 {s. V (s) }.
It becomes limit s->0 [(s+4)/(s+3)^2] = 4/9.
V(s /I(s) = (s+4)/(s+3)^2.
On substituting the value of I (S) i.e. 1/s we get.
V(s) = I(s)*(s+4)/(s+3)^2.
= (s+4)/((s)(s+3)^2).
Now when you use the formula for the steady state i.e. limit s->0 {s. V (s) }.
It becomes limit s->0 [(s+4)/(s+3)^2] = 4/9.
(1)
TABISH IQBAL said:
1 decade ago
From the final value theorem it is being solved.
Khalique said:
1 decade ago
How did you removed the term 1/s which makes whole transfer function infinite when s tends to zero? or you have applied L'Hospitals rule?
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