Electronics and Communication Engineering - Networks Analysis and Synthesis - Discussion

Discussion Forum : Networks Analysis and Synthesis - Section 11 (Q.No. 17)
17.
In following circuit, steady state is reached with S open, S is closed at t = 0, the current I at t = 0+ is given by
9 Ω
6 Ω
7 Ω
10 Ω
Answer: Option
Explanation:

When steady state is reached with s open, capacitor will act as open circuit

Current in 4Ω resistor will be = 6A at steady state.

Voltage across 4Ω = 6 x 4 24 volt.

Current in 2Ω resistor due to 6A 3A current due to 16 V, source.

I = 16/2 8A, this current divide in (2 + 2) Ω is 4Ω resistor current in 2Ω resistor 4A + 3A 7A.

Discussion:
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