Electronics and Communication Engineering - Networks Analysis and Synthesis - Discussion

Discussion Forum : Networks Analysis and Synthesis - Section 9 (Q.No. 36)
36.
In the circuit shown, the steady state is reached with S open S is closed at t = 0, the current I in the 1 Ω resistor connected is to be determined at t = 0+ is given by
1
2
3
4/3
Answer: Option
Explanation:

If steady is reached L will be short circuited the current in 1 Ω resistor I = 4/2 2A.

It will act as current source in parallel with inductor.

Now apply superposition theorem consider 4 volt source, current source will be open and inductor also open.

Current in R' = 1 Ω resistor = 2A.

When current source consider, voltage source will be short circuited and current due to inductor is 1A in opposite direction.

Total current 2 - 1 = 1 A.

Discussion:
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