Electronics and Communication Engineering - Networks Analysis and Synthesis - Discussion

According to me, the initial charge across the capacitor should be zero as the condition is given it is relax rc circuit. So still I have a doubt why not option b is the correct answer.

Can you explain in detail how relax capacitor have an initial charge? While solving this do we need to take an ideal capacitor where there is no input resistance or practical capacitor?

At t=0, c acts as short but according to the graph, there is a voltage drop which has to be because of a series resistor.

The are parallel to C will be shorted by because of C at t=0.

Why not A ?

In this also at t=0 some voltage is there.

It is not A, because initially at t=0 there is zero current flowing. Hence V drop across the resistance is zero and that across capacitor also is zero according to the initial condition which implies V across current source is also zero. It is not right from the given graph.

And why not A?

Because initially at t=0 there is some voltage across current source.

But for parallel combination of are and c initially capacitor will act as short circuit therefore there is 0 volt initial but that is not the case here.

Why it is not B?