Electronics and Communication Engineering - Networks Analysis and Synthesis - Discussion
Discussion Forum : Networks Analysis and Synthesis - Section 1 (Q.No. 2)
2.
The rms value of wave in figure is


Answer: Option
Explanation:
Discussion:
33 comments Page 1 of 4.
Abdul said:
3 years ago
Why didn't square the 100 from 1 to 2? Explain this.
(1)
Ruhama said:
5 years ago
Nice explanation.
Kriti Gupta said:
5 years ago
Why (100t) ^2 in a triangle and only 100t in rectangular? Explain, please.
Sanidhya said:
7 years ago
Actually, in the first integration the ramp signal is taken so it is 100t and in second integration the step signal is taken 100 (magnitude).
G.Thirunavukkarasu said:
7 years ago
The given signal consists of a ramp signal plus a dc signal.
The ramp signal has the RMS value of Vp/√(3).
the dc signal has the RMS value of dc value itself.
the total RMS value is;
√{(100^2)/3 + 100^2}.
This results 200/√(3).
The ramp signal has the RMS value of Vp/√(3).
the dc signal has the RMS value of dc value itself.
the total RMS value is;
√{(100^2)/3 + 100^2}.
This results 200/√(3).
(3)
Lobomo said:
7 years ago
Answer shoulld be 81.64.
(2)
Danielle Tampis said:
8 years ago
RMS or root mean square is the SQUARE ROOT of an area of a specific function SQUARED times (1/2) because of the word MEAN or AVERAGE value. In the given curve, it is divided into two parts.
1. From t = 0 to t = 1, the function is V = 100t (as you can see the value of V is 0 at t = 0 and 100 at t = 1 OR just use point slope form).
2. From t = 1 to t = 2, the area is like a square with sides measuring 100 units.
Therefore:
vrms = √{(1/2)(A1 + A2)},
Where:
A1 = Integral (100t)^2 dt, t = 0 to t = 1.
A2 = Integral (100)^2 dt, t = 1 to t = 2.
1. From t = 0 to t = 1, the function is V = 100t (as you can see the value of V is 0 at t = 0 and 100 at t = 1 OR just use point slope form).
2. From t = 1 to t = 2, the area is like a square with sides measuring 100 units.
Therefore:
vrms = √{(1/2)(A1 + A2)},
Where:
A1 = Integral (100t)^2 dt, t = 0 to t = 1.
A2 = Integral (100)^2 dt, t = 1 to t = 2.
(3)
Vijay said:
8 years ago
RMS= Root of Mean of Square.
As per the given formula...from 1to 2 it is 100^2.
=> root{1/2[10^4 + 10^4x[1/3] ]}.
=>root{1/2[10^4x[4/3] ]}.
=>root{10^4 x 2/3}.
=>100 x root{2/3}.
=>81.someting.
= 80(approx).
As per the given formula...from 1to 2 it is 100^2.
=> root{1/2[10^4 + 10^4x[1/3] ]}.
=>root{1/2[10^4x[4/3] ]}.
=>root{10^4 x 2/3}.
=>100 x root{2/3}.
=>81.someting.
= 80(approx).
(1)
Saniya said:
8 years ago
From interval 1 to 2 it should be 100^2.
Mukul said:
8 years ago
From 1 to 2 it should be 100^2.
And if we use 100^2 then answer is different.
And if we use 100 only still the answer is different.
And if we use 100^2 then answer is different.
And if we use 100 only still the answer is different.
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