Electronics and Communication Engineering - Networks Analysis and Synthesis - Discussion

Discussion Forum : Networks Analysis and Synthesis - Section 9 (Q.No. 28)

Networks Analysis and Synthesis

28.

Two current sources each of rms value 10 A have frequencies 40 Hz and 50 Hz respectively. They are connected in series, the expression for resultant wave is

i = 10 sin 40 t + 10 sin 50 t

i = 14.14 sin 40 t + 14.14 sin 50 t

i = 14.14 sin 80 pt + 14.14 sin 100 pt

i = 20 sin 80 pt + 20 sin 100 pt

Answer: Option

Explanation:

Peak value = 14.14 A; ω₁ = 2p x 40, ω₂ = 2p x 50

Discussion:

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