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Electronics and Communication Engineering - Networks Analysis and Synthesis - Discussion

Discussion Forum : Networks Analysis and Synthesis - Section 21 (Q.No. 33)
Networks Analysis and Synthesis
33.
For a symmetrical network
h11 = h22
h12 = h21
h11 h22 - h12 h21 = 0
h11 h22 - h12 h21 = 1
Answer: Option
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