Electronics and Communication Engineering - Microwave Communication - Discussion

Discussion Forum : Microwave Communication - Section 4 (Q.No. 42)
42.
If D is diameter of circular waveguide the cutoff wave-length for TE11 mode is equal to
1.706 D
2.11 D
0.82 D
0.41 D
Answer: Option
Explanation:

Some applications require dual polarization capability. Circular waveguide has this capability.

These analysis uses cylindrical coordinates.

In circular waveguide TE11 mode has the lowest cut off frequency and is the dominant mode.

If D is diameter of waveguide

λc = 1.706 D for TE11 mode

λc = 1.029 D for TE21 mode

λc = 0.82 D for TE01 mode

λc = 1.306 D for TM01 mode.

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