Electronics and Communication Engineering - Microprocessors - Discussion
Discussion Forum : Microprocessors - Section 1 (Q.No. 4)
4.
JCOKE = 3
JCOKE = JCOKE + 1
GO TO (5, 8, 9, 11, 15, 16 18, 20) JCOKE.After the execution of above statement, the control is transferred to statement number
Answer: Option
Explanation:
It is a computed GO TO statement. Since J COKE = 3 + 1 = 4, the control is transferred to statement 11.
Discussion:
15 comments Page 2 of 2.
Sandya said:
8 years ago
JCOKE = 3
JCOKE = JCOKE + 1
GO TO (5, 8, 9, 11, 15, 16 18, 20) JCOKE.
In this JCOKE is a variable name.It holds the number which points to the position in (5, 8, 9, 11, 15, 16 18, 20).
Since JCOKE is having 4, GOTO will point to the 4th position whose value is 11. Hence the answer is 11.
JCOKE = JCOKE + 1
GO TO (5, 8, 9, 11, 15, 16 18, 20) JCOKE.
In this JCOKE is a variable name.It holds the number which points to the position in (5, 8, 9, 11, 15, 16 18, 20).
Since JCOKE is having 4, GOTO will point to the 4th position whose value is 11. Hence the answer is 11.
(4)
ASHVANI JHA said:
7 years ago
How can I solve it? Can Anyone Explain in detail? Please.
Kit said:
7 years ago
Doesn't the position start from 0.
So jcoke (4) would be 15.
So jcoke (4) would be 15.
Rajesh. said:
7 years ago
Yes. I agree @kit!.
In assembly or any machine code, starting address is 0.
In assembly or any machine code, starting address is 0.
Sushama said:
6 years ago
Can someone resolve the conclusion?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers