Electronics and Communication Engineering - Microprocessors - Discussion
Discussion Forum : Microprocessors - Section 1 (Q.No. 4)
4.
JCOKE = 3
JCOKE = JCOKE + 1
GO TO (5, 8, 9, 11, 15, 16 18, 20) JCOKE.
After the execution of above statement, the control is transferred to statement number
Answer: Option
Explanation:
It is a computed GO TO statement. Since J COKE = 3 + 1 = 4, the control is transferred to statement 11.
Discussion:
15 comments Page 1 of 2.
Sandya said:
8 years ago
JCOKE = 3
JCOKE = JCOKE + 1
GO TO (5, 8, 9, 11, 15, 16 18, 20) JCOKE.
In this JCOKE is a variable name.It holds the number which points to the position in (5, 8, 9, 11, 15, 16 18, 20).
Since JCOKE is having 4, GOTO will point to the 4th position whose value is 11. Hence the answer is 11.
JCOKE = JCOKE + 1
GO TO (5, 8, 9, 11, 15, 16 18, 20) JCOKE.
In this JCOKE is a variable name.It holds the number which points to the position in (5, 8, 9, 11, 15, 16 18, 20).
Since JCOKE is having 4, GOTO will point to the 4th position whose value is 11. Hence the answer is 11.
(4)
Bhagya said:
1 decade ago
Given Jcoke = 3.
Jcoke = Jcoke+1.
So now Jcoke = 4, then it is go to 4th number in the sequence.
Jcoke = Jcoke+1.
So now Jcoke = 4, then it is go to 4th number in the sequence.
Sravani said:
1 decade ago
Here JCOKE = 3+1 = 4.
In goto statement jcoke (4) means 5-1, 8-2, 9-3, 11-4.
In goto statement jcoke (4) means 5-1, 8-2, 9-3, 11-4.
Rajesh. said:
7 years ago
Yes. I agree @kit!.
In assembly or any machine code, starting address is 0.
In assembly or any machine code, starting address is 0.
Kit said:
7 years ago
Doesn't the position start from 0.
So jcoke (4) would be 15.
So jcoke (4) would be 15.
ASHVANI JHA said:
7 years ago
How can I solve it? Can Anyone Explain in detail? Please.
Priyanka said:
1 decade ago
Can somebody explain why this answer came such?
Sushama said:
6 years ago
Can someone resolve the conclusion?
Mahi said:
9 years ago
What is the full form of JCOKE?
Priya said:
8 years ago
What is the full form of JCOKE?
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