Electronics and Communication Engineering - Measurements and Instrumentation - Discussion
Discussion Forum : Measurements and Instrumentation - Section 2 (Q.No. 32)
32.
Two voltmeters 0-250 V each having resistances of 5 kΩ and 10 kΩ respectively and are connected in series. To ensure that neither of them goes beyond scale the total voltage which can be applied should be less than
Answer: Option
Explanation:
or V = 375 V.
Discussion:
2 comments Page 1 of 1.
Shivani said:
5 years ago
Max m current which is capable in both voltmeters=250/10000.
Hence voltage = i * r
= (0.025) * (10+5) * 1000.
= 375.
Hence voltage = i * r
= (0.025) * (10+5) * 1000.
= 375.
CozCiti said:
6 years ago
It should be 250.
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