Electronics and Communication Engineering - Measurements and Instrumentation - Discussion

2. 

An ammeter of 0-25 A range has a guaranteed accuracy of 1% of full scale reading. The current measured is 5 A. The limiting error is

[A]. 2%
[B]. 2.5%
[C]. 4%
[D]. 5%

Answer: Option D

Explanation:

.


Imran said: (Apr 13, 2014)  
0.25/5 = 0.05x100 = 5%.

Anil said: (May 4, 2014)  
Please correct it.

% error = 0.25*100/5volt = 5%.

Sanju said: (Jul 6, 2014)  
Scale given 1% so 25x1/100 = 0.25A.

%error = 0.25/58x100 = 5%.

Shinykiran said: (Dec 10, 2015)  
How the value 58 came?

Sharada said: (Aug 21, 2016)  
What is the formula used here? Can anyone say?

Bindu said: (Apr 27, 2017)  
I am not understanding. Can anyone explain properly?

Rajeev said: (May 25, 2017)  
Here, (% error at desired scale * desired scale ) = (%error at full scale value * full scale value).

Mahesh Thapa Magar said: (Jul 21, 2017)  
%Error(DS) * DS = %Error(FS) * FS.

DS:Desired scale.
FS:Full SCale.

Mangai said: (Jul 21, 2017)  
Limiting error = accuracy * full scale reading = (1%) * 25 = (1/100) *25 = 0.25 A
error in percentage.

% error=(maximum error/scale reading) * 100 = (0.25/ 5) *100 = 5%.

Narender said: (Feb 26, 2018)  
1/25*100=4,
4/100*5=20/100,
= 5%.

Hasnain Khizar said: (Mar 12, 2018)  
@All.

It is actually the conversion from absolute and percentage error. The key is to understand them properly and especially their conversions and where to use which one.

Rayal Jp said: (Dec 19, 2018)  
(M.v-T.v/T.v) * 100.

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