Electronics and Communication Engineering - Measurements and Instrumentation - Discussion
Discussion Forum : Measurements and Instrumentation - Section 1 (Q.No. 2)
2.
An ammeter of 0-25 A range has a guaranteed accuracy of 1% of full scale reading. The current measured is 5 A. The limiting error is
Answer: Option
Explanation:
.
Discussion:
12 comments Page 1 of 2.
Rayal jp said:
7 years ago
(M.v-T.v/T.v) * 100.
Hasnain Khizar said:
7 years ago
@All.
It is actually the conversion from absolute and percentage error. The key is to understand them properly and especially their conversions and where to use which one.
It is actually the conversion from absolute and percentage error. The key is to understand them properly and especially their conversions and where to use which one.
Narender said:
8 years ago
1/25*100=4,
4/100*5=20/100,
= 5%.
4/100*5=20/100,
= 5%.
Mangai said:
8 years ago
Limiting error = accuracy * full scale reading = (1%) * 25 = (1/100) *25 = 0.25 A
error in percentage.
% error=(maximum error/scale reading) * 100 = (0.25/ 5) *100 = 5%.
error in percentage.
% error=(maximum error/scale reading) * 100 = (0.25/ 5) *100 = 5%.
(3)
Mahesh Thapa Magar said:
8 years ago
%Error(DS) * DS = %Error(FS) * FS.
DS:Desired scale.
FS:Full SCale.
DS:Desired scale.
FS:Full SCale.
Rajeev said:
8 years ago
Here, (% error at desired scale * desired scale ) = (%error at full scale value * full scale value).
Bindu said:
8 years ago
I am not understanding. Can anyone explain properly?
Sharada said:
9 years ago
What is the formula used here? Can anyone say?
Shinykiran said:
10 years ago
How the value 58 came?
Sanju said:
1 decade ago
Scale given 1% so 25x1/100 = 0.25A.
%error = 0.25/58x100 = 5%.
%error = 0.25/58x100 = 5%.
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