Electronics and Communication Engineering - Measurements and Instrumentation - Discussion
Discussion Forum : Measurements and Instrumentation - Section 3 (Q.No. 22)
22.
Two ammeters A and B are connected in parallel in a circuit carrying 100 A. Their resistances are 0.8 mΩ. Their readings will be.
Answer: Option
Explanation:
.
Discussion:
3 comments Page 1 of 1.
Nilogalp said:
8 years ago
100*1/1.8=55.56A.
100*.8/1.8=44.44A.
100*.8/1.8=44.44A.
MJ fan said:
10 years ago
I think the the ammeter resistances are 1 and 0.8 milli ohm.
G@^^ said:
1 decade ago
Whenever two ammeters connected in parallel of same R, they have to share same current.
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