Electronics and Communication Engineering - Measurements and Instrumentation
Exercise : Measurements and Instrumentation - Section 3
- Measurements and Instrumentation - Section 1
- Measurements and Instrumentation - Section 2
- Measurements and Instrumentation - Section 3
- Measurements and Instrumentation - Section 4
- Measurements and Instrumentation - Section 5
- Measurements and Instrumentation - Section 6
- Measurements and Instrumentation - Section 7
- Measurements and Instrumentation - Section 8
- Measurements and Instrumentation - Section 9
- Measurements and Instrumentation - Section 10
46.
Consider the following statements
- Thermistor is more sensitive than platinum resistance thermometer
- The resistance of thermistor is solely a function of its absolute temperature whether the source of heat is external or internal
- Thermistor has linear temperature-resistance relationship
- Thermistor has linear negative temperature coefficient
Answer: Option
Explanation:
Thermistor is a non-linear device.
47.
A moving coil meter has 10 Ω resistance and requires 40 mA for full scale deflection. The shunt resistance required to convert it into 0-2 A ammeter is
Answer: Option
Explanation:
.
48.
Which of the following instruments can be used for dc as well ac upto a few MHz?
- Moving iron instrument
- Thermocouple instrument
- Induction instrument
- Moving coil instrument
Answer: Option
Explanation:
Thermocouple instrument is based on heating effect and can be used for very high frequencies also.
49.
Assertion (A): Strain measurement using strain gauge invariably requires a dummy strain gauge.
Reason (R): The resistance of strain gauge depends on temperature.
Answer: Option
Explanation:
The dummy strain gauge compensates the error due to change in temperature because temperature affects both the active and dummy strain gauges equally.
50.
If a shunt of 200 Ω resistance is used with a galvanometer of 1000 Ω resistance, the multiplying power is
Answer: Option
Explanation:
If current through galvanometer is 1,
A current through shunt = . Total current = 6 I. Hence multiplying factor is 6.
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