Electronics and Communication Engineering - Materials and Components - Discussion
Discussion Forum : Materials and Components - Section 1 (Q.No. 8)
8.
The minority carrier life time and diffusion constant in a semiconducting material are 100 μs and 100 cm2/s respectively. The diffusion length of carriers is
Answer: Option
Explanation:
Diffusion length = sqrt(Carrier life time x Diffusion constant) = (100 x 10-6 x 100)0.5 = 0.1 cm.
Discussion:
11 comments Page 1 of 2.
Mayank raval said:
8 years ago
The diffusion length is related to the carrier lifetime by the diffusivity according to the following formula:
L = √Dτ.
where:
L is the diffusion length in meters;
D is the diffusivity in m2/s and,
τ is the lifetime in seconds.
L = √Dτ.
where:
L is the diffusion length in meters;
D is the diffusivity in m2/s and,
τ is the lifetime in seconds.
(5)
Ambigasri said:
9 years ago
Square root is equal to (x)^1/2 = x^0.5 [Carrier life time x diffusion con]^1/2.
OR
0.5,=(100x10^-6 x100)^0.5 = (10000/1000000)^0.5 = (1/100)^0.5 = 0.1cm.
OR
0.5,=(100x10^-6 x100)^0.5 = (10000/1000000)^0.5 = (1/100)^0.5 = 0.1cm.
Shradha said:
1 decade ago
@Prakash 100x10^-6 = 10^-4.100x10^-4 = 0.01.
0.01^0.5gives 0.1 cm. I wonder from where this 0.5 came?
0.01^0.5gives 0.1 cm. I wonder from where this 0.5 came?
Shweta said:
1 decade ago
Diffusion Length = Square root of (Diffusivity*Lifetime).
Prakash said:
1 decade ago
How could the answer is 0.1cm? can anyone explain this?
Uma said:
9 years ago
Sqrt of diffusion length = diffusion length^0.5.
Gouthami said:
1 decade ago
(100*10^-6*100)^0.5 = 100/10*10*10 = 0.1cm.
Kajale Aniruddha said:
9 years ago
Not understanding. Please explain this.
Vinay said:
1 decade ago
Can anyone tell how this 0.5 came?
Subburaj said:
1 decade ago
Square root of x = x^1/2 = x^0.5.
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