Electronics and Communication Engineering - Materials and Components - Discussion

4. 

If k is Boltzmann's constant and T is absolute temp, then at room temp.

[A]. kT 0.025 eV
[B]. kT 0.5 eV
[C]. kT 1 eV
[D]. kT 100 eV

Answer: Option A

Explanation:

No answer description available for this question.

Mohan Kumar said: (Oct 8, 2016)  
Thermal velocity is equal to the product of Boltzman Comtant *temperature/Q
Thermal velocity = T/11600.

At room temp.,
Thermal velocity = 273° + 27°/11600 = 300/11600 = 0.026 volt.

Rohan Yaav said: (Aug 13, 2017)  
Thermal voltage=(K * T)/Q.
K=boltzmann constant=1.38*10 to power -23.
T= Room temperature=300 kelvin.
Q= charge on one electron= 1.6 * 10 to power -19.

Since the answers are given in eV we have to calculate using above formulae.
Answer= ~0.025eV.

Post your comments here:

Name *:

Email   : (optional)

» Your comments will be displayed only after manual approval.