Electronics and Communication Engineering - Materials and Components - Discussion
Discussion Forum : Materials and Components - Section 4 (Q.No. 4)
4.
If k is Boltzmann's constant and T is absolute temp, then at room temp.
kT 
0.025 eV
0.025 eVkT 0.5 eV
0.5 eVkT 1 eV
1 eVkT 100 eV
100 eVDiscussion:
2 comments Page 1 of 1.
Rohan yaav said:
8 years ago
Thermal voltage=(K * T)/Q.
K=boltzmann constant=1.38*10 to power -23.
T= Room temperature=300 kelvin.
Q= charge on one electron= 1.6 * 10 to power -19.
Since the answers are given in eV we have to calculate using above formulae.
Answer= ~0.025eV.
K=boltzmann constant=1.38*10 to power -23.
T= Room temperature=300 kelvin.
Q= charge on one electron= 1.6 * 10 to power -19.
Since the answers are given in eV we have to calculate using above formulae.
Answer= ~0.025eV.
(1)
Mohan kumar said:
9 years ago
Thermal velocity is equal to the product of Boltzman Comtant *temperature/Q
Thermal velocity = T/11600.
At room temp.,
Thermal velocity = 273° + 27°/11600 = 300/11600 = 0.026 volt.
Thermal velocity = T/11600.
At room temp.,
Thermal velocity = 273° + 27°/11600 = 300/11600 = 0.026 volt.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers