Electronics and Communication Engineering - Exam Questions Papers - Discussion

Discussion Forum : Exam Questions Papers - Exam Paper 6 (Q.No. 47)
47.

ωH =
108 rad/sec
104 rad/sec
102 rad/sec
10 rad/sec
Answer: Option
Explanation:

R = 10 || 10 = 5 KΩ

.

Discussion:
Be the first person to comment on this question !

Post your comments here:

Your comments will be displayed after verification.