Electronics and Communication Engineering - Exam Questions Papers - Discussion
Discussion Forum : Exam Questions Papers - Exam Paper 4 (Q.No. 9)
9.
A sequential multiplexer is connected as shown in figure. Each time the multiplexer receives the clock, it switches to the next channel from 6 to 1. If the input signals are :
A = 10 cos 2p(4 x 103t)
B = 15 cos 2p(5 x 103t)
C = 20 cos 2p(6 x 103t)
D = 10 cos 2p(10 x 103t)
The minimum clock frequency should be __________ kHz.
A = 10 cos 2p(4 x 103t)
B = 15 cos 2p(5 x 103t)
C = 20 cos 2p(6 x 103t)
D = 10 cos 2p(10 x 103t)
The minimum clock frequency should be __________ kHz.
Answer: Option
Explanation:
Minimum clock freq. = 2fm
Where fm is highest freq. component = 2 x 10 kHz = 10 kHz.
Discussion:
Be the first person to comment on this question !
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers