Electronics and Communication Engineering - Exam Questions Papers - Discussion

Discussion Forum : Exam Questions Papers - Exam Paper 1 (Q.No. 23)
23.
The equivalent form of the logical expression ABC + A BC + ABC + ABC + AB C is
C + (A ⊕ B)
(A + B + C)(A + B + C)
(A + B + C)(A + B + C)(A + B + C)
(A + B + C)(A + B + C)(A + B + C)
Answer: Option
Explanation:

This can be solve by using Boolean identity but using k map it will be more easy

(A + B + C) (A + B + C) (A + B + C).

Discussion:
3 comments Page 1 of 1.

Ashitha said:   9 years ago
See the 0th position A'B'C'+AB'C+A'BC. Convert it to product of sum by negating it.

Rojisanvy said:   9 years ago
I'm not getting this.

Please explain the solution.

Rojisanvy said:   9 years ago
I can't understand the answer. How is it possible?

Could you please explain it in detail.

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