Electronics and Communication Engineering - Exam Questions Papers - Discussion

Discussion Forum : Exam Questions Papers - Exam Paper 6 (Q.No. 4)
4.
The equation for loop currents I1 and I2 are __________
Answer: Option
Explanation:

k = 0.8

M = kL1L2 = 0.83 x 2 = 1.95 H

Apply KVL to loop 1

200∠0° = (j5 + 5 + j2 - j3)I1 + 1.95I2

200∠0° = (5 + j4)I1 + j1.95I2

Apply KVL to loop 2

0 = (5 + 3 + j3)I2 + j1.95I1

0 = (8 + j3)I2 + j1.95I1

0 = j1.95I1 + (8 + j3)I2

The loop equations in matrix form are

Discussion:
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