Electronics and Communication Engineering - Exam Questions Papers - Discussion
Discussion Forum : Exam Questions Papers - Exam Paper 1 (Q.No. 47)
47.
Consider the probability density f(x) = ae-b|x| where x is a random variable whose allowable values range from x = - ∞ to x = + ∞. P(1 ≤ x ≤ 2)
(e-b - e-2b)
Answer: Option
Explanation:
P(x) = 
ae-b|x|dx
to get 
apply 
aebxdx + 
ae-bxdx,
we get 
= .
Discussion:
1 comments Page 1 of 1.
PUJA SHINDE said:
8 years ago
Please explain the answer.
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