Electronics and Communication Engineering - Exam Questions Papers - Discussion
Discussion Forum : Exam Questions Papers - Exam Paper 1 (Q.No. 2)
2.
A transmission line has a characteristic impedance of 50 Ω and a resistance of 0.1 Ω/m, if the line is distortion less, the attenuation constant (in Np/m) is
Answer: Option
Explanation:
Distortion less 
a = RG and Z0 = RG → 
.
Discussion:
24 comments Page 1 of 3.
Shweta said:
1 decade ago
Can anyone explain it further please?
Shweta said:
1 decade ago
Got it by myself.
Correct formula for distortionless transmission line is:
Characteristic impedance = Square root of (resistance/Conductance).
Correct formula for distortionless transmission line is:
Characteristic impedance = Square root of (resistance/Conductance).
Aditya said:
10 years ago
Z0= sqt of RG.
NeelU said:
10 years ago
Zo = sqrt(R/G).
(1)
Dilip N said:
10 years ago
G/C = R/L.
Zo = sqrt(L/C).
Zo = sqrt(R/G).
Zo = sqrt(L/C).
Zo = sqrt(R/G).
PAVI said:
9 years ago
Z0 = sqrt of RG.
SAI SURESH said:
9 years ago
I can't understand can any one explain this.
Jai2x said:
9 years ago
The real formula is Zo = sqrt(R/G) if you analyze the solution for number 2.
Sowmya said:
8 years ago
Can any 1 explain how 0.1/2500 came?
Rajesh said:
8 years ago
I understood the explanation.
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