Electronics and Communication Engineering - Exam Questions Papers - Discussion
Discussion Forum : Exam Questions Papers - Exam Paper 4 (Q.No. 3)
The equation sin (z) = 10 has
Discussion:3 comments Page 1 of 1.
Shiv Sagar said: 3 years ago
Answer: (x=(2n+1)x(pi/2),y=+/-(2.993)). So it should be (D) i.e. an infinite number of complex solutions.
Bemish said: 5 years ago
Here sin(Z) is unbounded in the complex plane.
Vanamali said: 8 years ago
Given answer is wrong. Z = 1.5708 - 2.9932i yields sin(z) = 10.
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