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Electronics and Communication Engineering - Exam Questions Papers - Discussion

Discussion Forum : Exam Questions Papers - Exam Paper 3 (Q.No. 42)
Exam Questions Papers
42.
Find the power absorbed or delivered by each source:
a = -32 b = - 12 c = -80 d = -60
a = -32 b = - 12 c = 80 d = 60
a = 32 b = 12 c = -80 d = 60
a = -32 b = 12 c = 80 d = -60
Answer: Option
Explanation:

Source a : Power : 8 x (4) = - 32 W. Source A has delivered the power as it is. - ve.

Source b: Source B has absorbed power of + 12 W as power is positive

Source c: Source C has absorbed power of 5 x 16 = 80 W

Source d: Delivers power of 3 x ix x (5) = 3 x 4 x (- 5) = -60 W

Total power of the network is - 32 + 12 + 80 - 60 = 0 Watts.

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