Electronics and Communication Engineering - Exam Questions Papers - Discussion

Discussion Forum : Exam Questions Papers - Exam Paper 5 (Q.No. 40)
40.
Find equivalent capacitance if each capacitance is 2 F.
5/12 F
12/5 F
6/5 F
5/6 F
Answer: Option
Explanation:

For capacitor take inverse of value of capacitance and then apply procedure same as in resistance case.

After getting the final answer take inverse of result to get Ceq

Ceq = F

In Cuboids case,

For resistance Req = R Ω with each R = 1

For inductance Leq = L H with each L = 1 H

For capacitance Ceq =CF with each C = 1 F.

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