Electronics and Communication Engineering - Exam Questions Papers - Discussion
Discussion Forum : Exam Questions Papers - Exam Paper 5 (Q.No. 40)
40.
Find equivalent capacitance if each capacitance is 2 F.


Answer: Option
Explanation:
For capacitor take inverse of value of capacitance and then apply procedure same as in resistance case.
After getting the final answer take inverse of result to get Ceq
∴ Ceq = F
In Cuboids case,
For resistance Req = R Ω with each R = 1
For inductance Leq = L H with each L = 1 H
For capacitance Ceq =CF with each C = 1 F.
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