Electronics and Communication Engineering - Exam Questions Papers - Discussion

30. 

The analog signal given below is sampled at 1200 samples per second. m(t) = 2 sin 120 pt + 3 sin 240 pt + 4 sin 360 pt + 5 sin 480 pt + 6 sin 600 pt + 7 sin 720 pt. The folding (maximum) frequency is __________ .

[A]. 300 Hz
[B]. 360 Hz
[C]. 600 Hz
[D]. 480 Hz

Answer: Option C

Explanation:

Folding frequency (max.) = = 600 Hz.


Ankit said: (Dec 14, 2016)  
Please explain it.

Jude said: (Aug 22, 2017)  
So the folding frequency minimum would be?

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