Electronics and Communication Engineering - Exam Questions Papers - Discussion

Discussion Forum : Exam Questions Papers - Exam Paper 3 (Q.No. 19)
19.
Find the maximum power that can be delivered to a load
0.025 W
2.5 W
2.5 W
0.25 W
Answer: Option
Explanation:

PL = I2R = x R •••(i)

where zS = 100 + j50

zL = 100 - j50

Putting the values in eq. (i)

PL =X l00 = 0.25 watts.

Discussion:
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