Electronics and Communication Engineering - Exam Questions Papers - Discussion
Discussion Forum : Exam Questions Papers - Exam Paper 5 (Q.No. 28)
28.
For the network shown below, if VD = 12 V and VGSQ = - 2 V value of RS will be
Answer: Option
Explanation:
VGS = VG - IDRS
- 2 = 5.44 - 2.22 X 10-3 X RS
RS = 3.35 KΩ.
Discussion:
1 comments Page 1 of 1.
Checi said:
6 years ago
In vg, you multiplied with 47k but in question given as 4.7k. Then what is the right answer?
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