Electronics and Communication Engineering - Exam Questions Papers - Discussion
Discussion Forum : Exam Questions Papers - Exam Paper 6 (Q.No. 14)
14.
(9)11 x (9)13 x(9)15 = (?)16
Answer: Option
Explanation:
(9 x 9 x 9)15 = (729)15 = (2D9)16 .
Discussion:
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