Electronics and Communication Engineering - Exam Questions Papers - Discussion

12. 

For the network shown below, determine fHi and fHO, if, r0 = ∞, Cbe = 36 Pf, Cbc = 4 Pf, Cce = 1 Pf, Cwo = 8 Pf, Cwi = 6 Pf

where Cwo = wiring capacitance at output side, Cwi = wiring capacitance at input side

[A]. 738.24 KHz, 8.6 MHz
[B]. 781.2 KHz, 10.6 MHz
[C]. 838.32 KHz, 9.2 MHz
[D]. 938.24 KHz, 8.2 MHz

Answer: Option A

Explanation:

Equivalent is

RTi = RS || R1 || R2 || Ri = 0.531 KΩ

Ci = Cwi + Cbe + (1 + AV)Cbc

= 6pf + 36pf + (1 - c - 90) 4 pf = 460 pf

RT2 = RC || RL = 4 K || 2.2 K = 1.419 KW

C0 = Cwo + Cce + CMO


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