Electronics and Communication Engineering - Exam Questions Papers - Discussion

A rectangular waveguide, in dominant TE mode, has dimensions 10 cm x 15 cm. The cut off frequency is

Answer: Option B

Explanation:

For TE₁₀ mode

Vasundhara said: (Aug 16, 2014)
In general dimensions of rectangle are represented as l:b. So a = 10cm, but here they have considered a = 15cm. Can any one help me to understand this?

Alok said: (Apr 13, 2015)
Answer will be 1.5 GHz. For TE mode we will consider a = 10 cm and f= (310^10) / (2a (cm)).

Santhosh said: (Apr 5, 2016)
Please explain clearly. I can't understand.

Gopal said: (Sep 19, 2016)
@Alok. I agree with your answer. For Dominant mode TE10. Cutoff frequency f = c/2a. Put all the value and we get our answer.

Gauri said: (Jan 20, 2018)
Yes, answer should be 1.5 GHz.

Rajesh said: (Feb 24, 2018)
Dominant mode is TE10 only when dimensions are a>b but here in the question he gave a<b so dominant mode will be TE01 so Cut-off frequency is C/(2b).

Navya Rekha said: (Mar 23, 2018)
@Gauri. Here a is wider band& b is narrow band means a=15,b=10. So,f=310^8 m/215 cm, 3*10^8/0.3=1ghz.

Thenmozhi said: (Nov 20, 2018)
@Gopal. What is "c" here?

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