Electronics and Communication Engineering - Exam Questions Papers - Discussion

The given signal can be expressed as multiplication of x₁(t) and x₂(t) as shown below.

where A = 2, T/2 = 0.25 => T = 0.5

∴ x(t) = x₁(t) x x₂(t)

=> X(f) = X₁(f) * X₂(f)

Now X₁(f) = [δ(f - f₀) + δ(f + f₀)]

= [sin c [T(f - f₀)] + sin c[T(f + f₀)]]

Now, A = 2, T = 0.5 and f₀ = = 1

=> X(f) = 0.5[sin c (0.5(f - 1)) + sin c (0.5(f + 1))].