Electronics and Communication Engineering - Exam Questions Papers - Discussion

Discussion Forum : Exam Questions Papers - Exam Paper 7 (Q.No. 20)
20.
An audio signal of FM radio station is sampled at a rate of 15% above the Nyquist rate. Signal is sampled in 512 levels and bandwidth of the signal is 4 KHz. The minimum bandwidth required to transmit this signal will be
77 K bits/sec
92 K bits/sec
84.8 K bits/sec
82.8 K bits/sec
Answer: Option
Explanation:

Nyquist rate = 2 x 4 kHz = 8 kHz

Sampling rate = 8 kHz + 1.2 kHz = 9.2 kHz

Number of bits required = log2512 = 9

Thus bandwidth = 9 x 9.2 = 82.8 k bits/sec.

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