Electronics and Communication Engineering - Exam Questions Papers - Discussion
Discussion Forum : Exam Questions Papers - Exam Paper 3 (Q.No. 14)
14.
(1 2 1)x = (1 0 0)4 Then x is equal to
Answer: Option
Explanation:
x2 = 2x + 1 = 16
x2 + 2x - 15 = 0, (x - 3)(x + 5) = 0, x = 3, - 5
Thus x = 3.
Discussion:
1 comments Page 1 of 1.
Kamaljeet Kainth said:
1 decade ago
(1 2 1) x = (1 0 0) 4.
Look for radix or base and solve for decimal value.
For example if we choose value of x=3 then.
(1 2 1)3 = (1 0 0)4.
= 1*3^2+2*3^1+1*3^0 = 1*4^2+0*4^1+0*4^0.
9+6+1 = 16+0+0.
16 = 16.
Look for radix or base and solve for decimal value.
For example if we choose value of x=3 then.
(1 2 1)3 = (1 0 0)4.
= 1*3^2+2*3^1+1*3^0 = 1*4^2+0*4^1+0*4^0.
9+6+1 = 16+0+0.
16 = 16.
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