Electronics and Communication Engineering - Electronic Devices and Circuits
Exercise : Electronic Devices and Circuits - Section 14
- Electronic Devices and Circuits - Section 13
- Electronic Devices and Circuits - Section 24
- Electronic Devices and Circuits - Section 23
- Electronic Devices and Circuits - Section 22
- Electronic Devices and Circuits - Section 21
- Electronic Devices and Circuits - Section 20
- Electronic Devices and Circuits - Section 19
- Electronic Devices and Circuits - Section 18
- Electronic Devices and Circuits - Section 17
- Electronic Devices and Circuits - Section 16
- Electronic Devices and Circuits - Section 15
- Electronic Devices and Circuits - Section 14
- Electronic Devices and Circuits - Section 1
- Electronic Devices and Circuits - Section 12
- Electronic Devices and Circuits - Section 11
- Electronic Devices and Circuits - Section 10
- Electronic Devices and Circuits - Section 9
- Electronic Devices and Circuits - Section 8
- Electronic Devices and Circuits - Section 7
- Electronic Devices and Circuits - Section 6
- Electronic Devices and Circuits - Section 5
- Electronic Devices and Circuits - Section 4
- Electronic Devices and Circuits - Section 3
- Electronic Devices and Circuits - Section 2
6.
Decimal 45.15 when converted into 9's complement will become
7.
Binary number 11011.01 when converted to its 2's complement will become
8.
A five bit binary adder is used to add 01001 and 00111. The adders from LSB position are numbered as FA0, FA1, FA2 and FA3. The outputs of FA2 are
9.
figure shows a NAND latch used as a switch debouncer. With the switch in STOP position. Q will be equal to
10.
The values of 25 in octal system is
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