Electronics and Communication Engineering - Electronic Devices and Circuits
Exercise : Electronic Devices and Circuits - Section 5
- Electronic Devices and Circuits - Section 13
- Electronic Devices and Circuits - Section 24
- Electronic Devices and Circuits - Section 23
- Electronic Devices and Circuits - Section 22
- Electronic Devices and Circuits - Section 21
- Electronic Devices and Circuits - Section 20
- Electronic Devices and Circuits - Section 19
- Electronic Devices and Circuits - Section 18
- Electronic Devices and Circuits - Section 17
- Electronic Devices and Circuits - Section 16
- Electronic Devices and Circuits - Section 15
- Electronic Devices and Circuits - Section 14
- Electronic Devices and Circuits - Section 1
- Electronic Devices and Circuits - Section 12
- Electronic Devices and Circuits - Section 11
- Electronic Devices and Circuits - Section 10
- Electronic Devices and Circuits - Section 9
- Electronic Devices and Circuits - Section 8
- Electronic Devices and Circuits - Section 7
- Electronic Devices and Circuits - Section 6
- Electronic Devices and Circuits - Section 5
- Electronic Devices and Circuits - Section 4
- Electronic Devices and Circuits - Section 3
- Electronic Devices and Circuits - Section 2
46.
The number of digits in hexadecimal system
Answer: Option
Explanation:
It has 16 digits 0 to 15.
47.
Which of these is the most recent display device?
Answer: Option
Explanation:
VF display can operate at very low voltages, has low power consumption and very long life.
48.
A NOR gate has 3 inputs A, B, C. For which combination of inputs is output HIGH
Answer: Option
Explanation:
NOR gate gives High output when all inputs are Low.
49.
In 2's complement form, - 2 is
Answer: Option
Explanation:
A = 1110,
A = 0001,
A + 1 = 0001 + 1 = 0010 = 2
Therefore A = -2.
50.
The Boolean function/implemented in the figure using two I/P multiplexers is
Answer: Option
Explanation:
when B = 1, f1 = ABC
B = 0, f2 = ABC
f = f1 + f2 = ABC + ABC.
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