Electronics and Communication Engineering - Electromagnetic Field Theory - Discussion
Discussion Forum : Electromagnetic Field Theory - Section 2 (Q.No. 21)
21.
A vertical wire of 1 meter length carries a current of 1 A at 10 MHz. The total radiated power is nearly
Answer: Option
Explanation:
P = I2 . R 
(1)2 . 73 73 watt.
Here, vertical wire will be considered as dipole.
Discussion:
4 comments Page 1 of 1.
MANDEEP SINGH SAINI said:
5 years ago
Total radiation Power Rr=80 pi*pi (le/λ)^2) where length is 1 meter and frequency = 10 M Hz. Wavelength = velocity of light/frequency
= 3*10^8/10* 10^6=1/900.
Rr=80 * 3.142 * 1/900 = 0.88 watt.
= 3*10^8/10* 10^6=1/900.
Rr=80 * 3.142 * 1/900 = 0.88 watt.
Faizan Madki said:
5 years ago
How did you calculate le and why you considered 790? Explain
Azad Pathak said:
5 years ago
Yes, it should be option B.
Rajeev said:
7 years ago
R=790((le/λ)^2)=0.8777,
P=I2 . R =(1)2 * .877=.877=.88,
Option B is correct.
P=I2 . R =(1)2 * .877=.877=.88,
Option B is correct.
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