Electronics and Communication Engineering - Electromagnetic Field Theory - Discussion
Discussion Forum : Electromagnetic Field Theory - Section 1 (Q.No. 47)
47.
The displacement flux density at a point on the surface of a perfect conductor is 
= 2(ax - 3 az)c/m2 pointing away from the surface. The charge density at that point c/m2 will be
= 2(ax - 3 az)c/m2 pointing away from the surface. The charge density at that point c/m2 will beAnswer: Option
Explanation:
∇ . D = r.
Discussion:
5 comments Page 1 of 1.
Awani said:
1 decade ago
Please explain clearly.
(1)
Bharti said:
9 years ago
Please explain it.
Atul verm said:
8 years ago
Simply take the mod of vector.
Yogesh said:
7 years ago
How it is possible? by unit δ unit is 1/meter and D unit is c/m2 is this way the overall unit is C/m3?
MaaKaBharosa said:
4 years ago
Here, the formula &del;.D= ρ.
But actually, this &del;.D value is only given in the sum.
Yes, right @Atul Verm.
But actually, this &del;.D value is only given in the sum.
Yes, right @Atul Verm.
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