Electronics and Communication Engineering - Electromagnetic Field Theory - Discussion
Discussion Forum : Electromagnetic Field Theory - Section 1 (Q.No. 16)
16.
Consider a 300 Ω, quarter wave long at 1 GHz transmission line as shown in figure. It is connected to a 10 V, 50 Ω source at one end is left open circuited at the other end. The magnitude of the voltage at the open circuit end of the line is
Answer: Option
Explanation:
γ = a + jβ a = 0 
γ = jβ
Propagating wave
v = VI e-rz + VR erz
No change in the voltage at the open end it will same,
vr = 10 volt.
Discussion:
4 comments Page 1 of 1.
Kanchan chaudhary said:
9 years ago
60V is the correct Answer.
Jaykishan said:
8 years ago
60V is correct.
Sai said:
8 years ago
How did you get 60v?
Jeeva said:
7 years ago
Z0/Zl=300/50 = 60.
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